Solving the functional $\min \int_0^1xy^2+x^3y\;dx$

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I'm having a course on Calculus of Variations and I'm doing my first homework problems. One of them is the following:

Determine the smooth extremum which satisfies the boundary conditions for:

$$\min \int_0^1xy^2+x^3y\;dx,\;\;\;y(0)=A, \;y(1)=B,$$

where $y=y(x)$.

Can someone guide me how to solve this problem correctly? What I tried is the following:

I know that in order for $y^*$ be the optimal solution for the functional, then it must satisfy the Euler-Lagrange equation:

$$\frac{\partial F}{\partial y}-\frac{d}{dx}\left(\frac{\partial F}{\partial y'}\right)=0,$$

where in my problem $F(x,y,y') = xy^2+x^3y$ and $y'=\frac{dy}{dx}$. By applying the E-L equation I get:

$$2xy+x^3=0,$$

from where I solve that $$y=-\frac{1}{2}x^2.$$

Where should I apply the boundary conditions now? Did I make a mistake somewhere or is this how I'm supposed to solve it? Thank you for your help =)

Or does the boundary conditions in this case mean that: $y(0)=A=0 $ and $y(1)=B=-\frac{1}{2}$?

P.S. here is my problem in its original form:

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