The height of a ball is thrown directly upward from an initial height of $160$ ft with an initial velocity of $48$ ft per second is given by the function:
$s(t) = -16t^2 + 48t + 160$, where $s(t)$ gives the ball's height above ground in feet, $t$ seconds after it is thrown. How long will it take for the ball to hit the ground?
HINT
You have a quadratic so, if you factor it and you will find the roots or in other words, when the balls hits the ground.
HINT $2$
HINT $3$