Spectral theorem - Why is $\mathbb{A}(v)=k^TA^Tc$?

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say $\mathbb{A}:V\rightarrow V$ is a linear and symmetric function with V an $\mathbb{R}$-vector space.

If $c=(c_1,...,c_n)$ is a orthonormal basis of $V$ (not spectral basis), $A$ the matrix of $\mathbb{A}$ regarding that basis (spectral theorem), $v=\sum_{i=1}^n v_i\cdot c_i, k=(v_1,...,v_n)\in\mathbb{R}^n$, then why is

$\mathbb{A}(v)=(Ak)^Tc=k^TA^Tc$?

Thank you!