I am studying for quiz. I want to find stationary vector for $$\begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}$$
I drew the markov picture and tried $x = xP$ but did not get a solution. Does it mean that the stationary distribution does not exist?
Any vector $x$ satisfies the condition
$$ x = x P $$
where $P$ is the identity matrix. The other conditions you need for $x$ to be a stationary distribution are