In the Neveu-Schwarz sector, the worldsheet fermions can be expanded as
$$ \psi^I(\tau,\sigma) \sim \sum\limits_{r\in Z+1/2}b_r^Ie^{-ir(\tau-\sigma)} $$
and the total mass squared operator can then be written as
$$ M^2 = \frac{1}{\alpha'}\left( \frac{1}{2} \sum\limits_{p\neq 0} \alpha_{-p}^I\alpha_p^I + \frac{1}{2}\sum\limits_{r\in Z+1/2} r \, b_{-r}^I b_r^I \right) $$
The first sum gives the contribution of the bosons, the second one the contributions of the fermions.
Why are the summands in in the fermionic part multiplied by $r$, how does this factor come in mathematically? Does this have something to do with the Pauli exclusion principle?
The same thing issue appears with the fermionic part mass operator in the Ramond sector, where I dont understand it either ...
If one solves the field equations for the bosonic field, with the Newmann/Dirchilet/Closed String Boundary conditions, one can see that the mode expansion is something like:
$$X^\mu=...+i\sqrt{2\alpha'} \sum_{n\neq0 }^{ } \frac{\alpha^\mu}{n}\exp\left(in\sigma^0\right)\cos\left(n\sigma^1\right)$$
On the other hand, the fermionic field mode expansion goes like:
$$\psi^\mu_\pm = \frac1{\sqrt2}\sum_{n\in\mathbb Z \ \mathrm{or} \ \mathbb{Z}+\frac12 }b_r^\mu \exp\left(-ir\sigma^\pm\right) $$
Notice that there is a missing factor of $\frac1r$ in the second equation.
$[N,b_{-r}^\mu]=rb_{-r}^\mu$ and the conclusion follows.