According to a theorem from van Engelen: Homogeneous zero-dimensional absolute Borel sets (1986):
Theorem: If $X$ is a separable metrizable zero-dimensional absolute $F_{\sigma\delta}$ that is nowhere $G_{\delta\sigma}$ and of the first category (in itself), then $X \simeq \mathbb{Q}^\omega$ .
My question is: do similar conditions as im the Theorem apply for any other spaces that are strongly zero-dimensional?
If not with similar assumptions, the conditions can be even very different from those in the theorem. But I am interested whether for any other strongly zero-dimensional space $Y$, there exists $X$ such that $X \simeq Y$ under some assumptions.
I am thinking that maybe Cantor set or irrationals could have similar property, but not very sure. Also I am not 100% sure if Cantor set and irrationals are strongly zero-dimensinal or just zero-dimensional.
In the following I will mean by space a (non-empty) separable metrisable space.
For a space zero-dimensional and strongly zero-dimensional are equivalent, as is well known. So you can forget about that distinction in the remaining part.
Some classical theorems:
Then Aleksandrov and Urysohn asked (in their 1928 paper) for other characterisation theorems like this, but for higher Borel classes. Similar I think to what you want. So it's an old problem area.
If you want more info on some solutions to this see van Engelen's thesis which has proofs for all of the above too and his own characterisation of $\Bbb Q^\omega$ that you referenced. I won't repeat that info here. But it gets really technical and quite deep later on. (I've followed a one semester class/seminar on descriptive set theory by van Engelen during my studies).