$\sum a_n$ converges $\implies\ \sum \sqrt{a_na_{n+1}}$ converges?

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Let $a_n > 0.$ When $\sum a_n$ converges $\sum \sqrt{a_n a_{n+1}}$ converges or not?

For, $$\frac{\sqrt{a_n a_{n+1}}}{a_n}=\frac {\sqrt{a_{n+1}}} {\sqrt{a_n}}$$

$\because$ By comparison test $\sum \sqrt{a_n}$ converges, $$\lim_{n\to\infty} \frac {\sqrt{a_{n+1}}} {\sqrt{a_n}}=1\neq0$$

Therefore by limit comparison test $\sum \sqrt{a_n a_{n+1}}$ converges.

Is this proof correct?

Corrections will be greatly appreciated...