Polynomials over $\mathbb{Q}$ can exhibit "geometrical symmetries" in different ways, graph-wise (as functions $P:\mathbb{R} \rightarrow \mathbb{R}$) and root-wise:
$P(x) = P (-x)$
(axial symmetry along $y$-axis)$P(x) = -P (x)$
(central symmetry)$P(x) = \prod_{k=-n}^n (x + k)$: all roots are real and have the same consecutive distance
(translational symmetry)$P(x) = \sum_{k=0}^{2n} x^k$: all roots are complex, have the same norm and the same consecutive distance
(rotational symmetry)For each polynomial $P(x)$ the complex roots come in conjugate pairs.
(axial symmetry along $x$-axis)
I wonder which other "geometrical symmetries" of polynomials, their graphs and their roots are there - and how these symmetries do possibly relate to the permutational symmetries as reflected in the Galois group of a polynomial.
You can get rotational symmetry of arbitrary order for the set of real zeros of bivariate polynomials.
One way of generating such polynomials is to use the arithmetic of complex numbers. For hopefully obvious reason the cubic $$ R_3(x,y):=\operatorname{Re}\left((x+iy)^3\right)=x^3-3xy^2 $$ has the property that if $(x',y')$ is the point we get by rotating $(x,y)$ 120 degrees about the origin, then $R_3(x',y')=R_3(x,y)$.
Therefore it is obvious that the set of solutions of the polynomial equation $$(x^3-3xy^2)+\frac16=(x^2+y^2)^2$$ exhibits this 3-fold rotational symmetry.
Similarly using $R_5(x,y)=\operatorname{Re}\left((x+iy)^5\right)=x^5-10x^3y^2+5xy^4$ we get 5-fold rotational symmetry in the zero locus of the polynomial $$(x^5-10x^3y^2+5xy^4)+1-(x^2+y^2)^3.$$
I included a non-zero constant term and a high enough power of $(x^2+y^2)$ to guarantee that the set of solutions is a compact subset of $\Bbb{R}^2$, and that there is no singularity at the origin.
A few more remarks: