$t(x) - t(x/2) + t(x/3) - t(x/4) + ... = 0$ implies $t(x) + t(x/2)+t(x/3)+t(x/4) = C x$?

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Inspired by this mysterious function :

$f(x) + f(x/2) + f(x/3) + f(x/4) + ... = x$ and $\lim_{n \to \infty} \frac{f(n)}{\pi(n)} = 1$?

I started to wonder since the alternating sum equals zero :

$$f(x) - f(x/2) + f(x/3) - f(x/4) + ... = 0$$

Do we have for every solution

$$t(x) - t(x/2) + t(x/3) - t(x/4) + ... = 0$$

the implication

$$t(x) + t(x/2)+t(x/3)+t(x/4) = C x$$

For some constant $C$ ??