Given two perpendicular lines with intersection point A. We have two equal sized circles positioned with the centers on the horizontal line. The circles centers are an equal distances from point A. We want to find point P that is the intersection between the vertical line and the lower horizontal tangent between the two circles.
I found link 1 that explains how to find the tangent between two circles in general but my question is if this can be simplified when the circles are of equal size or if there is some other simple way of finding point P.
The distance from A to the center of the circle is not the radius of the circle. The distance is smaller so the circles are overlaping.