Taylor series for tetration

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I would like to know what is known about Taylor series for tetration (and other hyper-exponentiations).

Surprisingly, such information is rare on internet. Numerical values for expansion in hyperexponent for tetration with basis $e$ can be found here:

http://en.citizendium.org/wiki/Tetration#Taylor_expansion_at_zero

However I am interested in expansion in the basis of tetration. I look for

$$ x \uparrow \uparrow m = \sum_{n=0}^{\infty} c_n(m)x^n $$

Wolfram mathematica gives me wired result (obviously a bug) at $x=0$ for $x \uparrow 3$:

https://www.wolframalpha.com/input/?i=taylor+series+x%5E(x%5Ex)

where in the output $log(x)$ appears (not a polynomial).

It is better at $x=1$

https://www.wolframalpha.com/input/?i=taylor+series+x%5E(x%5Ex)+at+x%3D1

I imagine the point $x=0$ may be "peculiar", but at least expansion at $x=1$ should be possible.

List of my questions:

1) Is tetration analytic at $x=0$? At $x=1$?

2) If yes, is an explicit closed-form formula for $c_n(m)$ known? (at any of these points)

3) If not, is an explicit closed-form formula for $c_n(m)$ know for some specific values of $m$?

4) Same questions for extension to higher hyper-exponentiations...

Thank you.

2

There are 2 best solutions below

0
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Consider the tetration of the function $e^x$ $$^n(e^x)=(e^x)_1^{(e^x)_2^{(e^x)_3^{_..^{.e^x_n}}}}$$

For a natural number n, the taylor series of that function is

$$^n(e^x)=\sum_{k}^{\infty}\frac{1}{k!}*T(n,k)*x^k$$

where $T(n,k)$ is the OEIS A210725 (if k<n, $T(n,k)=T(k,k)$)

then, for $n\in\mathbb{N}$:

$$^n(x)=\sum_{k}^{\infty}\frac{1}{k!}*T(n,k)*(ln(x))^k$$

On the limit for $n\to\infty$, the T(n,k)=T(k,k) are the coefficients of the Lambert w function.

There are other series, that you can find here.

For code able to calculate tetrations with high precision, (for a limited set of bases, and $n\in\mathbb{R}$) check Sheldonison's fatou.gp code

In Wolframalpha, you can get the series of $^n(x+1)$, and it will produce the Stirling transform of $^n(e^x)$. The series has power of x, and no logarithms.

2
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Just for your curiosity.

Expanding as Taylor series aound $x=1$ as $$f_n=\sum_{k=0}^\infty c_k\,(x-1)^k$$ see how fast converge the coefficients $$f_1=\left\{1,1,1,\frac{1}{2},\frac{1}{3},\frac{1}{12},\frac{3}{40},-\frac{1}{120},\frac{59} {2520},-\frac{71}{5040},\frac{131}{10080}\right\}$$ $$f_2=\left\{1,1,1,\frac{3}{2},\frac{4}{3},\frac{3}{2},\frac{53}{40},\frac{233}{180},\frac{56 27}{5040},\frac{2501}{2520},\frac{8399}{10080}\right\}$$ $$f_3=\left\{1,1,1,\frac{3}{2},\frac{7}{3},3,\frac{163}{40},\frac{1861}{360},\frac{33641}{504 0},\frac{8363}{1008},\frac{22391}{2160}\right\}$$ $$f_4=\left\{1,1,1,\frac{3}{2},\frac{7}{3},4,\frac{243}{40},\frac{3421}{360},\frac{71861}{504 0},\frac{54371}{2520},\frac{69281}{2160}\right\}$$ $$f_5=\left\{1,1,1,\frac{3}{2},\frac{7}{3},4,\frac{283}{40},\frac{4321}{360},\frac{102941}{50 40},\frac{85871}{2520},\frac{61333}{1080}\right\}$$ $$f_6=\left\{1,1,1,\frac{3}{2},\frac{7}{3},4,\frac{283}{40},\frac{4681}{360},\frac{118061}{50 40},\frac{106661}{2520},\frac{81583}{1080}\right\}$$ $$f_7=\left\{1,1,1,\frac{3}{2},\frac{7}{3},4,\frac{283}{40},\frac{4681}{360},\frac{123101}{50 40},\frac{115481}{2520},\frac{93013}{1080}\right\}$$ $$f_8=\left\{1,1,1,\frac{3}{2},\frac{7}{3},4,\frac{283}{40},\frac{4681}{360},\frac{123101}{50 40},\frac{118001}{2520},\frac{97333}{1080}\right\}$$ $$f_9=\left\{1,1,1,\frac{3}{2},\frac{7}{3},4,\frac{283}{40},\frac{4681}{360},\frac{123101}{50 40},\frac{118001}{2520},\frac{97333}{1080}\right\}$$