If I have the expression:
$\langle\phi|\hat{A}$ $ \otimes \hat{I}|\phi\rangle$ $ $ $ $$ $(*)
where
$\hat{A}$ is a linear operator
$\hat{I}$ is the identity operator and
$| \phi \rangle \in \mathbb{C^2}\otimes \mathbb{C^2}$ and $\langle\phi|\phi\rangle=1$
Can I simplify (*) any further? Is it equal to $0$?