Let $B = \mathbb R[x,y]$ where $x^2 + y^2 = 1$ (called the coordinate ring of the unit circle).\
I want to prove that $\mathbb C \otimes_{\mathbb R} B$ is a UFD. I know that we are tensoring up with scalars but how this will help me in proving that it is a UFD.
I know that: a unique factorization domain is an atomic integral domain in which factorization to irreducibles is unique (up to associates). And a commutative ring is atomic if each $r \in R$ is a finite product of irreducibles in R.
Any help is appreciated.
Ok, here's the plan:
Here are some hints: in order for the map $\mathbb{C}[t,t^{-1}] \to \mathbb{C}[x,y]/(x^2+y^2-1)$ to be surjective, the image of $t$ must generate the codomain as a $\mathbb{C}$-algebra. In order for the map $\mathbb{C}[x,y]/(x^2+y^2-1) \to \mathbb{C}[t,t^{-1}]$ to be surjective, the image must contain $t$ and $t^{-1}$. In particular, you need $t$ to correspond to a unit in $\mathbb{C}[x,y]/(x^2+y^2-1)$ -- think about the factorization of $x^2 + y^2$ over $\mathbb{C}$ to find this unit!
Hope this helps! Happy to fill in more details if you get stuck somewhere.