the distribution of Martinet

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The distribution of Martinet is $\Delta=ker\omega$ with

$\omega=\Bbb dt-\frac{1}{2}y^{2}\Bbb dx$.

let $X=\partial x+\frac{1}{2}y^{2}\partial t$ and $Y=\partial y$

The curvature $2$-forme is: $\Omega=\Bbb d\omega$

so $\Omega=y\Bbb dx \wedge \Bbb dy$

I want to calculate $\Omega(X,Y)=y\Bbb dx \wedge \Bbb dy(X,Y)$.

I know how to calculate it in the Heisenberg case ($4\Bbb dx \wedge \Bbb dy$), but I don't know how in the Martinet case because of the unknown $y$.

should I fix the $y$, or is there something else I have to do?

Any help !!