The formula $P = 1,527,000 (1.015)^t$ gives the population $t$ years after 2008. Find the population in
(a) 2009
(b) 2010
What is the answer and a proper solution to this problem?
This is all about logarithmic and exponential functions.
2026-03-28 06:10:18.1774678218
The formula $P = 1,527,000 (1.015)^t$ gives the population $t$ years after 2008. Find the population in 2009 and 2010?
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This is a simple substitution
In 2009 one year has passed, so put $t=1$ into your equation, and for 2010 there have been $2$ years, so put $t=2$ in.