The sum of two consecutive even integers is 404. Find the double of the first.

Question

This exercise is giving me trouble. Could you please help me?

"The sum of two consecutive even integers is 404. Find the double of the first."

let be the first even number $x$

the secound $x+2$

The equation would be:

$x+x+2=404$

When solving the equation it gives me: $x=201$

So the first number would be $201$ and the second $203$

But that number is not even. So I don't know if is the exercise is ill-posed or if I just need to answer that there a not two even that their sum is $404$.

Thanks for helping.

Answer 1

If the sum of an odd real number and an odd imaginary number can be considered even, then one solution is $\quad \big((201-i), (203+i)\big)$.