The tensor $\epsilon_{ijk}$ is related to determinants?

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My textbook says the following in an appendix on tensor notation:

The tensor $\epsilon_{rst} = \begin{cases} 0 \qquad & \text{unless $r, s,$ and $t$ are distinct} \\ +1 \qquad & \text{if $rst$ is an even permutation of $123$} \\ -1 \qquad & \text{if $rst$ is an odd permutation of $123$} \end{cases}$

The tensor $\epsilon_{ijk}$ is related to determinants: for three contravariant tensors $a^i$, $b^j$, and $c^k$, one verifies that $a^i b^j c^k \epsilon_{ijk}$ is the determinant of the $3 \times 3$ matrix with rows $a^i$, $b^j$, and $c^k$.

I don't understand what this excerpt is saying:

The tensor $\epsilon_{ijk}$ is related to determinants: for three contravariant tensors $a^i$, $b^j$, and $c^k$, one verifies that $a^i b^j c^k \epsilon_{ijk}$ is the determinant of the $3 \times 3$ matrix with rows $a^i$, $b^j$, and $c^k$.

I would greatly appreciate it if people could please take the time to elaborate on this and demonstrate what is being referred to.

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If you look at the rule of sarrus for $3\times3$ matrices you find that the determinant is a sum of products of the matrix elements https://en.wikipedia.org/wiki/Rule_of_Sarrus.

The formula $a^ib^jc^k\epsilon_{ijk}$ gives exactly that: It is a sum of products of three matrix elements together with the tensor which is $0,-1$ or $1$.