The transformation matrix of an dimetric projection onto the plane Z=0

293 Views Asked by At

I need to make a dimetric projection of the point onto the Z=0 plane. I found the transformation matrix of an isometric projection onto the Z=0 plane and it looks like this:

\begin{align*} M &= \left[\begin{array}{cccc} cos (b) & 0 & -sin(b) & 0 \\ 0 & 1 & 0 & 0 \\ sin(b) & 0 & cos(b) & 0\\ 0 & 0 & 0 & 1 \\ \end{array}\right] \left[\begin{array}{cccc} 1 & 0 & 0 & 0 \\ 0 & cos(a) & sin(a) & 0 \\ 0 & -sin(a) & cos(b) & 0\\ 0 & 0 & 0 & 1 \\ \end{array}\right] * Morth(Z=0) \end{align*}

As a result, I`ve got: \begin{align*} M &= \left[\begin{array}{cccc} cos (b) & sin(b)*sin(a) & 0 & 0 \\ 0 & cos(a) & 0 & 0 \\ sin(b) & -sin(a)*cos(b) & 0 & 0\\ 0 & 0 & 0 & 1 \\ \end{array}\right] \end{align*} But I cannot find such similar information about dimetric projection. How should the matrix look like in my case?