The two circles are externally tangent as shown in the figure.If the radius of bigger and smaller circles are 6 and 2 respectively.Then the area of quadrilateral $PQSR$ is
$(A)24\sqrt3\hspace{1 cm}(B)12\sqrt3\hspace{1 cm}(C)12\hspace{1 cm}(D)24$
I tried and thought hard but no known formula or method seems to come at aid.Please help me.

Hope you can continue with that.
This is the final version with minor mistakes corrected:-