At LaGuardia Airport for a certain nightly flight, the probability that it will rain is $0.13$ and the probability that the flight will be delayed is $0.18$. The probability that it will not rain and the flight will leave on time is $0.79$. What is the probability that the flight would be delayed when it is not raining?
Im not sure with my solution:
$A$:event that it rains
$B$ : event that flight is delayed
P(A)=0.13
P(B)=0.18
P((NOT A) AND (NOT B))= 0.79
1- P(A OR B)= 0.79
P(A OR B)= 0.21
P(A OR B) = P(A) + P(B) - P(A AND B)
0.21=0.13 +0.18 - P(A AND B)
P(A AND B)=0.1
P(B|(NOTA)) = 0.18-0.1=$\boxed{0.08}$
the sentence is a little ambiguous. If you mean "flight delayed AND not raining " your result is correct.
But if you mean "flight delayed given that it is not raining" the result is $\frac{8}{87}$