Given that $P(x, y): “x + 2y = xy”$, where $x$ and $y$ are integers. How do we translate
$\lnot$$\forall$$x$ $\exists$$y$ $\lnot$$P(x,y)$
and what's the truth value of this?
Given that $P(x, y): “x + 2y = xy”$, where $x$ and $y$ are integers. How do we translate
$\lnot$$\forall$$x$ $\exists$$y$ $\lnot$$P(x,y)$
and what's the truth value of this?
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$¬∀ ∃ ¬(,)$
Use the negated quantifiers,
$∃ ∀ (,)$.
This statement is True when there exists x, for all y, P(x,y) holds.
Suppose that $x=x_0$ exists,
Require to Prove: for all y, $P(x_0,y)$ holds for all $y \in Z$.
Given that (,):“+2=”, where and are integers.
Require to Prove: $(_0,):“_0+2=_0”$ holds for all $y \in Z$.
Require to Prove: $(_0,):“_0+2=_0”$ holds for all $y \in Z$.
Require to Prove: $(_0,):“\frac{_0}{x_0-2}=, (x_0≠2)”$ holds for all $y \in Z$.
This is not true as there exists y = 1, $(_0,)$ doesn't hold as $x_0≠x_0 -2$.
Hence, the statement is False.