Trig/Vector question

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I have no idea where to go from here. I only know how to compute dot product, cross product, cos(theta), magnitude, projection, and scalar components but I don't know how to do this

Word Problem

This is as far as I've gotten so far in trying to wrap my head around this after watching numerous videos on youtube:

Triangle with vectors

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There are 2 best solutions below

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Hint: Horizontal component of a vector $V$ is $|V| cos(\theta)$. Hint 2: Take your horizontal direction to be parallel to inclined plane.

Note that angle of F with inclined plane is $34^\circ-16^\circ = 18^\circ$.

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This was a lot easier than I expected.

$$|w|cos(16°)=2.8$$ will then be $$|w|=\frac{2.8}{cos(16°)}$$ $$|w|=2.91$$