My problem is from Israel Gelfand's Trigonometry textbook.
Page 48. Exercise 5: d) $\frac{\sin\alpha}{1+\cos\alpha}=\frac{1-\cos\alpha}{\sin\alpha}$
I would appreciate some hints on how to approach the problem.
My problem is from Israel Gelfand's Trigonometry textbook.
Page 48. Exercise 5: d) $\frac{\sin\alpha}{1+\cos\alpha}=\frac{1-\cos\alpha}{\sin\alpha}$
I would appreciate some hints on how to approach the problem.
Hint: Note that $\sin^2\alpha = 1 - \cos^2\alpha$ and the latter expression is a difference of two squares.