I'm having trouble solving this equation.It looks simple, but I just can't find the answer.Can someone help me?
$$9x^4-13x^2+4 = 0$$
2026-04-13 10:42:00.1776076920
Trouble solving polynomial equation with exponent
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Let $t = x^2$ then we have $9t^2 - 13t + 4=0$
This factorises to give $(9t-4)(t-1)=0$ so our solutions are $t = \frac{4}{9}$ or $t=1$.
So $x = \pm\frac{2}{3}$ or $x=\pm1$.