Trouble with infinite summation involving $\sin$ function

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How can I proceed for this:

$$\sum_{n=-\infty}^{+\infty}{\bigg(\frac{\sin{(an+b)}}{an+b}\bigg)^2}$$

I know the answer is $\frac{\pi}{a}$, but how? I think it could be related to the Shannon sampling theorem, but any alternative solution would help as well.