Is the binary operation define by: $x*Y = x+y-1$
what my tutor has done: $x*(y*z) = x *(y+z -1) = x+(y+z-1) = x+y+z-2$
My question: how did he get $x+y+z$-2
Where did the '-2' come from?
I am simply trying to learn how he did this, thanks guys.
Is the binary operation define by: $x*Y = x+y-1$
what my tutor has done: $x*(y*z) = x *(y+z -1) = x+(y+z-1) = x+y+z-2$
My question: how did he get $x+y+z$-2
Where did the '-2' come from?
I am simply trying to learn how he did this, thanks guys.
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There's a little mistake
$x*(y*z) = x *(y+z -1) = x+((y+z-1)\color{red}{-1}) = x+y+z-2$