$$\frac{(2n+3)!}{(2n+1)!}$$
I solved the above problem and I got $(2n+3)(2n+2)$, but I inputted it onto my TI92 plus. It gives me: $\frac{(2n+3)!}{(2n+1)(2n)!}$ Any ideas?
$$\frac{(2n+3)!}{(2n+1)!}$$
I solved the above problem and I got $(2n+3)(2n+2)$, but I inputted it onto my TI92 plus. It gives me: $\frac{(2n+3)!}{(2n+1)(2n)!}$ Any ideas?
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