In Durrett's textbook, the strong Markov property is defined as follows:
For every bounded and measurable $\varphi$ and stopping time $N$: $$\mathbb{E}(\varphi\circ\theta_N|\mathcal{F}_N)=\mathbb{E}_{X_N}(\varphi) \tag{1}$$
But I think the strong markov property should be: $$\mathbb{E}(\varphi(X_N,X_{N+1},\cdots)|\mathcal{F}_N)=\mathbb{E}(\varphi(X_N,X_{N+1},\cdots)|X_N) \tag{2}$$ for every bounded and measurable $\varphi$.
I want to deduce (2) from (1).
update:
First I suppose $\varphi=\varphi(\omega_0,\omega_1,\cdots)$ in (1)
then $$\mathbb{E}_{X_N}(\varphi) =\sum_{k=0}^\infty\mathbb{E}(\varphi(\omega_0,\omega_1,\cdots)|X_0=k)1_{\{X_N=k\}}\overset{\text{time homogeneous}}{=}\sum_{k=0}^\infty\mathbb{E}(\varphi(\omega_N,\omega_{N+1},\cdots)|X_N=k)1_{\{X_N=k\}}=\mathbb{E}(\varphi(\omega_N,\omega_{N+1},\cdots)|X_N)$$ so we have: $$\mathbb{E}(\varphi(\omega_N,\omega_{N+1},\cdots)|\mathcal{F}_N)=\mathbb{E}(\varphi(\omega_N,\omega_{N+1},\cdots)|X_N)$$
the reasoning above is right or not ?
Hint: Take the conditional expectation (with respect to the $\sigma$-algebra generated by $X_N$) in $(1)$ and use the tower property.