Two little problems about convergence in distribution

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Hey I want to see if I have done everything right proving this statements:

Let $(X_n)n∈N$ independent, identically distributed random variables with $X_i ∼ N (0, 1)$. Be also $Z ∼ N(0, 1)$. For all $n ∈ N$ let be defined:

$Y_n:= \frac{X_1+...+X_n}{n}$ and $Z_n:= \frac{X_1+...+X_n}{\sqrt{n}}$

I have to prove that $Y_n \overset{D}{\rightarrow}0$ and $Z_n \overset{D}{\rightarrow}Z$.

For the first statement I have done this:

In the Script we had that if $Y_n$ converges in distributions towards a constant $c$ than $Y_n \overset{D}{\rightarrow} c$

Than $P(|X_1+...+X_n|>zn)\leq \frac{Var(X_1+...+X_n)}{n^2z^2}=\frac{n}{n^2z^2}=\frac{1}{nz^2}\overset{\infty}{\rightarrow}=0$

For the second statement I thought doing like this: $\lim_{n\rightarrow\infty}P(X_1+...+X_n\leq z\sqrt{n})=P(\frac{(X_1+...+X_n)-nµ}{\sqrt{nσ^2}}\leq\frac{z\sqrt{n}-nµ}{\sqrt{nσ^2}}=z)=\Phi(z)$

Is everything right? Have I done any errors?

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For the convergence of $Y_n$, you have to specify that $z$ is fixed and positive, and also justify that the variance of the sum $X_1+\dots+X_n$ is the sum of variances.

For the second part, you cannot have that that a limit as $n$ goes to infinity equal something depending on $n$. Also, you have to justify that $(X_1+\dots+X_n)/\sqrt n$ has a standard normal distribution.