In a metrizable topological vector space $X $ with the metric $d $, a subset A is said to be bounded if it can be absorbed by any neighbourhood of $0$ and a subset A is said to be d-bounded if its diameter with respect to the metric d is finite. Boundedness always implies d-boundedness, but the converse is not true.
I am looking for a condition for which d-boundedness implies boundedness. In the Wikipedia wiki, in the section "Topological vector spaces'', there is a statement, "The two notions of boundedness coincide for locally convex spaces''. But there is no reference for it there. Can somebody give some reference or some hint to prove this statement?
The simplest example is $\mathbb{R}$ with the metrics $d_1(x,y)=|x-y|$ and $d_2(x,y)=|\arctan(x)-\arctan(y)|$. These two metrics define the same topology. The definition of bounded with absorption is a topological property and does not depend on which metric you choose. $d$-boundedness depends on the metric.