two positive real numbers have their sum, product...

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Two positive real numbers have their sum,product and difference of the squares $(a^2-b^2)$ equal. Find those numbers. It would be easy to solve if only two of these were mentioned, but I don't know how to incorporate all three (sum,pro,diff) in an equation

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Let $a, b$ be two positive real numbers. And we have $a+b = ab = (a^2-b^2) = (a+b)(a-b)$.

We have that $a-b=1$ since $a+b \neq 0$. Can you continue...