Two smoothly homotopic smooth maps induce same maps on de Rham cohomology

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Let $a$, $b: M \to N$ be smoothly homotopic smooth maps. How do I see directly that $a$ and $b$ induce the same maps on de Rham cohomology? I know I want to construct a suitable chain homotopy between complexes of forms, but I am at a loss at how to do so. Could anybody help?