Assume $A,B$ are real-value symmetric matrix (maybe redundant condition) and $\lambda \in \mathbb{R}$. This question comes from here, but the answerer doesn't give the condition.
2026-04-06 14:18:09.1775485089
Under what conditions of $A,B$ we have $\det (A + \lambda B)$ is uniformly $0$ for all $\lambda$?
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