Understanding a parameter $\beta $ in a bayesian Poisson model

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I would like to know the meaning or signification of a parameter $\beta$ in a Bayesian model. I have a Poisson model like this

$s_{i} \mid \lambda_{i} \sim Poisson(\lambda_{i}t_{i})$

Where

$\lambda_i\mid\beta\sim\mathcal{G}a(\lambda_i\mid 1.8,\beta)$

and

$\beta\sim\mathcal{G}a(\beta\mid 0.01,1)$

I have as data the next table (which can be found in an article called Robust Empirical Bayes Analyses of Event Rates by O'Muircheartaigh & Gaver ):

System fails ($s_{i}$) time ($t_{i}$)
$1$ $5$ $94.32$
$2$ $1$ $15.72$
$3$ $5$ $62.88$
$4$ $14$ $125.76$
$5$ $13$ $5.24$
$6$ $19$ $31.44$
$7$ $1$ $1.048$
$8$ $1$ $1.048$
$9$ $4$ $2.096$
$10$ $22$ $10.48$

I tought that it was a kind of priori knowledge but it seems an interpretation too much simplistic. Is something hide that I am not taking into account? Is something that is going to be revealed to me afterwards when I try to find the posterior distribution?

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It's a hierarchical prior: there's an additional prior on a parameter of the first level prior.

Here is how to derive the unconditional distribution of $\lambda_i$. There's a trick: write $\mathcal{G}(1.8, \beta) = \frac{2}{\beta}\mathcal{G}(1.8, \frac12) = \frac{2}{\beta}\chi^2_{3.6}$.Now write $\mathcal{G}(0.001, 1) = 2\chi^2_{0.002}$. Finally one has $\lambda_i \sim \frac{\chi^2_{3.6}}{\chi^2_{0.002}}$ with independent numerator and denominator. This looks like a Fisher distribution but the degrees of freedom factors are missing. Actually this is a Beta prime distribution $\beta'(1.8, 0.001)$. Because of the derivation I've just shown, it is sometimes called the Gamma-Gamma distribution.