Determine which of the reflexive, symmetric, and transitive properties are satisfied by the given relation R defined on set S...
S= {1,2,3}
R= {(1,1), (1,3), (2,2), (2,3), (3,1), (3,2), (3,3)}
I've concluded that it is not reflexive due to that there is no (1,2) or (2,1) in R. I'm not too confident to say its not symmetric... Basically would anyone be able to properly simplify an explanation on how to find whether its reflexive, transitive, and/ or symmetric?
Reflexivity means that for all $x \in S$, we have that $(x,x) \in R$. Looking at your example, we see that $(1,1), (2,2)$ and $(3,3)$ are in $R$, so this relation is reflexive.
Symmetry of a relation means that if $(x,y) \in R$, then $(y,x) \in R$. This is the case: we have that $(1,3) \in R$ and so is $(3,1)$. Analogous for $(2,3)$. Note that neither $(1,2)$ nor $(2,1)$ is in $R$, but this is not a problem, since symmetry of a relation states that $\textbf{if}$ $(x,y) \in R$ $\textbf{then}$ $(y,x) \in R$. So if $(x,y)$ is not in $R$, we don't need to worry about $(y,x)$ being in $R$.
Transitivity of a relation means that if $(x,y \in R$ and $(y,z) \in R$, then so is $(x,z)$. This is not the case, can you find a counter example?