I've been learning about natural deduction recently and I'm having some trouble understanding it's meaning.
My main reference is the book "A Concise Introduction to Mathematical Logic" by Wolfgang Rautenberg. In this book they use the following notation $$\frac{X \vdash \alpha}{X \vdash \beta}$$ where $X$ is a set of formulas and $\alpha, \beta$ are formulas. Unfortunately, in the book there is no rigorous definition of this "fraction-notation", so I'm just left with an intuitive understanding. Could someone explain what exactly this "fraction" stands for and how the above statement is different from writing $${X \vdash \alpha} \implies {X \vdash \beta}?$$
A specific example that I'm struggling with:
My intuitive understanding leads me to believe that the statement $\frac{X \vdash \alpha}{X \vdash \beta}$ is "equivalent" to the statement $\frac{X \vdash \lnot \beta}{X \vdash \lnot \alpha}$. But how does one go about proving something like this, and in what sense are they "equivalent"?
I am very confused by these notions and would appreciate any help!
See page 22 (3rd ed ) :
And page 23 :
Thus, an inference rule is a "basic" allowable step in the calculus of the derivability relation : $\vdash$.
Having e.g. a derivation $X \vdash \alpha, \beta$, the application of the rule $\land_1$ licences us to attach to this derivation (a finite list of sequents) the new sequent : $X \vdash \alpha \land \beta$.
See again page 22 :
This result is [page 28] :
You have to note that $\Rightarrow$ and $\Leftrightarrow$ are meta-linguistic symbols, abbreviating "if ___, then ___" and "___ if and only if ___" respectively, and not part of the calculus [see page xxi].
Derivable rules [see page 23] are "patterns of inference" not included into the initial list of rules but that can be proved to be valid on the basis of the initial rules.
Regarding you example of a derived rule, it is not correct; contraposition must be written (in Rautenberg's system) as :
We can derive it as follows :
1) $X, \alpha \vdash \beta$ --- supposition
2) $X, \lnot \beta, \alpha \vdash \beta$ --- (MR) on 1
3) $X, \lnot \beta, \alpha \vdash \lnot \beta$ --- (IS), (MR)
4) $X, \lnot \beta, \alpha \vdash \lnot \alpha$ --- ($\lnot$-1) on 2 and 3
5) $X, \lnot \beta, \lnot \alpha \vdash \lnot \alpha$ --- (IS), (MR)