Understanding the notation $\nabla_n K_{bd}$ for covariant derivatives, with $n$ a vector

Question

I am having troubling interpreting a particular expression in differential geometry. It arose in computing the Lie derivative along a unit normal, $n$, of the extrinsic curvature of a sub-manifold embedded in spacetime. Specifically,

$$\mathcal{L}_n K_{bd} = \underbrace{\nabla_n K_{bd}}+(\nabla_b n^c)K_{cd} + (\nabla_d n^c)K_{bc} = \underbrace{\nabla_n K_{bd}} + 2K_{bc}K^c_d$$

I do not know how to make sense of what looks like a covariant derivative $\nabla_n$. Normally, the subscript is an index, but in this case $n$ is a vector. So I can only assume that $\nabla_n$ is compact notation for something else.

Source: The notation was encountered at roughly 25:00 minutes on the Perimeter Institute lecture available at: http://pirsa.org/displayFlash.php?id=12020017.

Answer 1

This means $$\nabla_n T_{\dots} = n^a \nabla_a T_{\dots}$$