how to use geometric mean to calculate computer performance? the 2.2 units The performance of computers COM A and COM B was compared by benchmark using three programs. When geometric mean is used as the evaluation scale, The performance of COM B was twice that of COM A (COM B has better performance). What is the execution time of program 3 in COM B?
program | Execution time on COM A (seconds) | Execution time on COM B(sec)
1 | 12 |9
2 | 6 |3
3 | 24 | ??
the root is 3 i thought becuase COM B is 2 times than COM A then $\frac{\sqrt[3]{9.3.x}}{\sqrt[3]{12.6.24}}=\frac{2}{1}$
but why is the right answer $\frac{\sqrt[3]{9.3.x}}{\sqrt[3]{12.6.24}}=\frac{1}{2}$? why is that(?)