Using Cauchy's Integral Theorem Solve $\int_{C} e^{\frac{1}{z}}$ where $c$ is $|z| = 1$

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The answer for the above question is given as $0$ in my college textbook. But when I read the actual theorem, it is written that the function must be analytic everywhere inside and on the curve. However here the exponential function is not analytic at the point $z=0$. Then how does the integral become $0$? Please bear with me as I am a beginner.