Using the Epsilon-N Definition of limits of sequences

Question

I think I have a proper understanding of the general procedure, but I'm having difficulty manipulating my inequality so that I can isolate $n$ by itself. Sadly I wasn't given many examples to model my answer on.

Prove that $$\lim_{n\to\infty} \frac{1}{n(n-1)} = 0.$$

Answer 1

Hint: $\dfrac{1}{n(n-1)} < \dfrac{1}{n}$.