Usual augmentation filtration? (Sigma algebra generated by a descreasing family of sets)?

514 Views Asked by At

My aim is to understand the usual augmentation filtration, for example as given in the appendix in the book Financial Derivatives in Theory and Practice: Revised Edition by P.J. Hunt and J.E. Kennedy.

Let $(\Omega,{\cal F}^\circ,\mathbb{P})$ be a probability triple. The $\mathbb{P}$-completion $(\Omega,{\cal F},\mathbb{P})$ of $(\Omega,{\cal F}^\circ,\mathbb{P})$ is the probability triple defined by ${\cal F}=\sigma({\cal F}^\circ \cup {\cal N})$, where $${\cal N}:=\{A\subset \Omega: A\subseteq B\mbox{ for some }B\in{\cal F}^\circ\mbox{ with }\mathbb{P}(B)=0\}.$$

The usual augmentation $(\Omega,\{{\cal F}_t\},{\cal F},\mathbb{P})$ of the filtered probability space $(\Omega,\{{\cal F}^\circ_t\},{\cal F}^\circ,\mathbb{P})$ is produced by taking ${\cal F}$ to be the $\mathbb{P}$-completion of ${\cal F}^\circ$ and by defining $${\cal F}_t:=\sigma({\cal F}^\circ_{t+}\cup {\cal N}) =\bigcap_{s>t} \sigma({\cal F}^\circ_{s}\cup {\cal N})$$ for all $t\geq 0$.

From this, I have a question:

Do we have the following identity?

$$\sigma(\cap_{i \ge 1}C_i)=\cap_{i \ge 1}\sigma(C_i)$$

Here $C_i$ is a family of subsets of $\Omega$

and $C_1 \supset C_2 \supset C_3....$ is a subset of a set Ω.