$V= 3b + 2b^2$ - what's the value of $V$ when $b=4$?

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Do I multiply $4$ to the power of $2$ or do I multiply $8$ to the power of $2$? What is the answer? I'm thinking it's $76$.

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You have $$3 \times 4+2 \times 4^2=12+2 \times 16=12+32=44$$

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$$V=3b+2b^2$$

So, when $b=4$, we get $$V=3\times4+2\times4^2=12+(2\times16)=12+32=44$$