The question that I am trying to answer is the following:
*Two sets A and B contains a and b elements respectively. If power set of A contains 8 more elements than that of B, value of ‘b’ and ‘a’ are respectively
a) 3, 4
b) 5, 6
c) 1, 2
d) None of the mentioned*
I assumed that by 'value', the size or cardinality is meant. And so, I just simply used 2^n.
By plugging in 3 and 4, I got 8 and 16 respectively. Since the question mentions that A has eight more elements, then I supposed that my answer, letter A, satisfies that because the difference of 16 and 8 is 8.
Is my assumption correct, or did I do something along the way?
You did it right.
A set with $n$ elements has a power set of cardinality $2^n$.