I'm having some difficulty understanding the difference between two ways that ordinals appear to be defined. One way is an ordinal $\beta$ is defined by:
$V_\beta := \mathcal{P}(V_\beta)$
And results in the following ranked ordinals:
$V_0 := \emptyset = \emptyset$
$V_1 := \{0\} = \{\emptyset\} $
$V_2 := \{0, 1\} = \{\emptyset, \{\emptyset\}\} $
Then the successor ordinal $\alpha$ is defined slightly different (no power set) by:
$S(\alpha) = \alpha \space \cup \{\alpha\}$
Can anyone explain the difference between $V_\beta$ and $S(\alpha)$? I would expect the successor to be the next ranked ordinal $V_\beta$, however after expanding $V_3$ these two definitions are not equal:
$V_{3a} = S(V_2) = \{0, 1, 2\} = \{\emptyset, \{\emptyset\}, \{\emptyset, \{\emptyset\}\}\}$
while:
$V_{3b} = \mathcal{P}(V_2) = \{0, 1, 2, ?\} = \{\emptyset, \{\emptyset\}, \{\{\emptyset\}\}, \{\emptyset, \{\emptyset\}\}\}$
Note: $V_{3b} \backslash V_{3a} = \{\{\emptyset\}\} $
I'm hoping to get this down as it seems like it forms a basis for future learning. Any insight appreciated. Thanks!
The $V_\alpha$ are not ordinals. They are the ranks of the Von Neumann hierarchy, which are indexed by the ordinals.
However, they do have a similarity. The ordinal $\alpha$ is the set of all ordinals less than $\alpha$. $V_\alpha$ is the set of all sets with rank less than $\alpha$.