We continually throw one dice until we get a specific result for first time

Question

I have a problem with exercise. Basically, I am not sure if I am right and how should it be. That's why if you can solve it so I will understand. I am reading this but I have difficulties and I am trying alone. The exercise says:

We throw continually one dice until we have succeeded for the first time a result below than 3.What is the possibility, to be more than 3 tries, until succeed the given result (the number to be smaller than 3)?

What I did I take this type from possibilities of Geometry: $f(x)=p(1-p)^{x-1}$ but I am not sure until now if this is the type or another. I believe this is it from what I have read

Answer 1

You require the score on each of the first 3 tries to be in {3,4,5,6}.

The probability is therefore $(\frac {4}{6})^3$.

Answer 2

You want the probability that you don't succeed (in getting a number below $3$) in the first three trials. This means you want the first three outcomes to be $3,4,5$ or $6$. The answer is $(\frac 4 6)(\frac 4 6)(\frac 4 6)=(\frac 2 3)^{3}$