Weak limit of product of two weakly converging sequences (counterexample)

380 Views Asked by At

Let $\Omega$ be an open, bounded subset of $\mathbb{R}^N$. I'm looking for an example of two sequences $u_n$ and $v_n$ in $L^2(\Omega)$ such that $$u_n \to u \ \mbox{weakly in}\ L^2(\Omega),$$ $$v_n \to v \ \mbox{weakly in}\ L^2(\Omega),$$ but the product $u_n v_n$ doesn't weakly converge to $uv$.

1

There are 1 best solutions below

4
On BEST ANSWER

Take $u_n=v_n\colon x\mapsto \sin(nx)$. Then $(u_n)_n$ weakly converges in $L^2(0,2\pi)$ to $0$ but $u_nv_n$ converges weakly to $\pi$, as $\sin^2u=\frac 12-\frac 12 \cos(2u)$.