My teacher's notes:
"For any $n\geq1$, "congruent mod $n$" defines an equivalent relation on $\Bbb{Z}$ and therefore, partition $\Bbb{Z}$ into $n$ different congruences classes"
What does any of that mean?
My teacher's notes:
"For any $n\geq1$, "congruent mod $n$" defines an equivalent relation on $\Bbb{Z}$ and therefore, partition $\Bbb{Z}$ into $n$ different congruences classes"
What does any of that mean?
On
An equivalence relation $R$ on a set $S$ means that for $x,y,z \in S$ that $xRy \implies yRx$, $xRx$ for all $x$ and if $xRy$ and $yRz$ then $xRz$.
A partition of a set is a collection of subsets of the set that have no elements in common with any other subset and every element of the set is in one of the subsets. You can think of this as organizing the elements of the set into different groups with no groups having any common element.
By the fundamental theorem of equivalence relations every partition is an equivalence relation and every equivalence relation is a partition. I would argue this is the most important theorem in modern mathematics and is the workhorse of many results in algebra, topology and analysis.
Because of this we sometimes give a special label to the partitions induced by the equivalence relation and in this case they're being called congruence classes. This will generalize to the idea of a coset in an algebraic group.
Correction: it should say "defines an equivalence relation on $\mathbb{Z}$". The background knowledge used here is:
Now, armed with that knowledge... I presume your teacher has proven that the relation "congruent mod $n$" on $\mathbb Z$ is an equivalence relation. It immediately follows that $\mathbb Z$ is partitioned into equivalence classes, which (speaking of congruences) we can call "congruence classes modulo $n$".
Example: $n=5$. The relation on $\mathbb Z$ is $x\equiv y\mod 5$, and so the congruence classes are the following five subsets:
Any two numbers from each set are congruent (modulo $5$) and there aren't two numbers from different sets that are congruent (modulo $5$).