$a_0 = 3$
$a_n = (a_{n-1})^2 + (a_{n-2})^2 +\cdots + (a_0)^2$ for all integers $n\geq 1$.
Would that mean $a_1 = a_0^2 = 9$?
Thanks!
$a_0 = 3$
$a_n = (a_{n-1})^2 + (a_{n-2})^2 +\cdots + (a_0)^2$ for all integers $n\geq 1$.
Would that mean $a_1 = a_0^2 = 9$?
Thanks!
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