$$\vec{AB} = \vec{CD}$$
For a moment, I had thought that
$$A = C \\ B = D$$
Which is not necessarily true - this was a little counter-intuitive for me, because I see vectors $\vec{XY}$ as "arrows with position", and thus it seemed natural for me that two vectors $\vec{AB}$ and $\vec{CD}$ should have the same position to be equal - which is not true. So I was wondering if there is another property related to equality that I may be misinformed of. Therefore:
What are the implications of
$$\vec{AB} = \vec{CD}$$
?
As far as I am concerned:
- $\vec{AB}$ is parallel to $\vec{CD}$
- The distance between $A$ and $B$ is the same as from $C$ to $D$.
$\|\vec{AB}\|=\|\vec{CD}\|$. Also, the directions of the two vectors are the same, i.e., they are parallel, not antiparallel. All their corresponding components are equal.