What does "almost everywhere invertible" mean?

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I'm reading the paper On differentiability in the Wasserstein space and well-posedness for Hamilton–Jacobi equations in which there is a paragraph

There is a special non-commutative group related to the isometry $\sharp: \mathbb{H} / \sharp \rightarrow \mathcal{P}_{2}\left(\mathbb{R}^{d}\right)$, namely the set $\mathcal{G}(\Omega)$ of Borel maps $S: \Omega \rightarrow \Omega$ (they lie in $\mathbb{H}$ ) that are almost everywhere invertible and have the same law as the identity map $\operatorname{id}$.

Here

  • $\Omega$ is the ball of unit volume in $\mathbb{R}^{d}$, centered at the origin.

  • $\mathbb{H}:=L^{2}\left(\Omega, \mathrm d x, \mathbb{R}^{d}\right)$.

My naïve guess is that "almost everywhere invertible" means the Lebesgue measure of $\{\omega \in \Omega \mid \operatorname{card}(S^{-1}(\omega)) \le 1\}$ is $1$.

Could you elaborate on this notion?

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When something happens almost everywhere, this means by definition that the set of points where it doesnt happens has zero measure. In your situation, the set of points where maps $S$ are not invertible has zero measure.
$m(\{x\in\Omega|S(x)$ not invertible$\})=0$.